Answer: Each bulb current ( I = P/V = 10/220 = 1/22 , \text{A} ) Number = total current / bulb current = ( 5 / (1/22) = 110 ) bulbs
Answer: ( H = I^2 R t = 5^2 \times 20 \times 30 = 25 \times 20 \times 30 = 15000 , \text{J} ) In-Text Questions (Page 220) Q1. What determines the rate at which energy is delivered by a current? Answer: Electric power ( P = V \times I = I^2 R = V^2 / R ) class 10 electricity ncert solutions
Answer: (i) 9 Ω = two in parallel (3 Ω) + one in series (6 Ω) (ii) 4 Ω = two in series (12 Ω) in parallel with one (6 Ω): ( 1/R = 1/12 + 1/6 = 3/12 ) → R=4 Ω Answer: Each bulb current ( I = P/V
Answer: Alloys have higher resistivity and do not oxidize easily at high temperatures. class 10 electricity ncert solutions