Vector Mechanics For Engineers Statics 12th Edition Solutions _top_ -

Calculate the magnitude and direction of the resultant force.

F1x = 100 cos(30°) = 86.60 N F1y = 100 sin(30°) = 50 N F2x = 150 cos(60°) = 75 N F2y = 150 sin(60°) = 129.90 N Calculate the magnitude and direction of the resultant force

MO = √(800^2 + (-600)^2) = 1000 N·m

MO = (3(0) - 4(0))i - (2(0) - 4(200))j + (2(0) - 3(200))k = 0i + 800j - 600k E. Russell Johnston Jr.

by Ferdinand P. Beer, E. Russell Johnston Jr., David F. Mazurek, and Michael E. Plesha is a widely used textbook in engineering mechanics courses. Here's a deep dive into the solutions of this book: David F. Mazurek

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